Revision as of 19:40, 17 June 2017

$xor returns the binary XOR of the 2 parameters.

Synopsis

$xor(<N1>,<N2>)

Parameters

N1 = 1st Number N2 = 2nd Number Both numbers must be base 10, fractions are ignored. Returns 0 if either number is 2^32 or greater 1.

Properties

None

Example

XOR is "Exclusive OR" comparison of a pair of bits. It returns 0 if BOTH or NEITHER are 1-bits, and returns 1 if exactly 1 of the pair is a 1-bit. In effect, every 1-bit in the 2nd number toggles the 0/1 state of the corresponding bit of the 1st number

//echo -a $xor(21,9)
; returns 28

Here's how the answer was calculated:

1. Convert each number to binary, then line them up vertically so there are 2 rows, where each position pair is a single column.
2. Create a 3rd row, where each column's 0 or 1 value is the XOR of the bit pair directly above it
3. Convert the 3rd row from binary to base 10.

//echo -a $base(21,10,2,8) | echo -a $base(9,10,2,8) | echo -a $str(-,8) | echo -a $base($xor(21,9),10,2,8)
; returns:
00010101
00001001
--------
00011100

The columns where both numbers are zero remain 0. The columns where only 1 of the 2 values is 1, and the column where both values were 1 is zero.

$xor then returns the answer in base 10. Depending on which bits have changed to 0 or 1, the answer can be less than or greater than the 2 numbers:

//echo -a $base(00011100,2,10)
; returns 28

Compatibility

Added: mIRC v5.61
Added on: 23 Sep 1999
Note: Unless otherwise stated, this was the date of original functionality.
Further enhancements may have been made in later versions.

See also

• $or
• $and
• $not
• $biton
• $bitoff
• $isbit
• List of identifiers - mIRC