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Here we have a break-down of the results of this regex:
 
Here we have a break-down of the results of this regex:
 
* The '''\6''' doesn't mean anything, as there are not 6 back-references made in the pattern (only one backreference, the pattern will, however, be applied 6 times and more because of the /g modifier)
 
* The '''\6''' doesn't mean anything, as there are not 6 back-references made in the pattern (only one backreference, the pattern will, however, be applied 6 times and more because of the /g modifier)
* When ''a'' is matched, '''\n''' is ''1'', and only one marker is used. Therefore, '''$1''' (used to represent \6) is filled with ''$regml(1 + 6 -1) = $regml(6)'', which is '''f'''
+
* When ''a'' is matched, '''\n''' is ''1'', and only one marker is used. Therefore, '''$1''' is filled with ''$regml(1 + 6 -1) = $regml(6)'', which is '''f'''
 
* When ''b'' is matched, '''\n''' is ''2'', '''$1''' is then filled with ''$regml(2 + 6 - 1) = $regml(7)'', which is '''g'''
 
* When ''b'' is matched, '''\n''' is ''2'', '''$1''' is then filled with ''$regml(2 + 6 - 1) = $regml(7)'', which is '''g'''
 
* And so on until '''\n + N - 1''' is greater than the total number of back-references, which at this point, '''$null''' is used.
 
* And so on until '''\n + N - 1''' is greater than the total number of back-references, which at this point, '''$null''' is used.

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