Editing number system

'''Number systems''' are a mathematical notation for representing numbers of a given [[number set|set]]. They are the foundation for conveying, quantifying, and manipulating [[data]].

Number systems are mainly classified according to [[number notation|notations]] ([[positional notation]] vs [[sign-value notation]]) and their [[base]]. Today, we largely use the [[Arabic numerals]] which is a [[base-10]] positional notation numbering system. Machines on the other hand may use a different number system - such as the [[base-2]].

== Notation ==
In the [[positional notation]], numbers are a string consisting of one or more juxtaposed digits. For example, [[fixed-point form]] number '''N''' takes the following form:

::<math>N_r = (d_{n-2} d_{n-1} \cdots d_2 d_1 d_0 \cdot d_{-1} d_{-2} d_{-3} \cdots d_{-m})_r</math>

Where '''r''' is the [[radix]] or the number of digits in the number system and '''d''' are the digits defined for that given radix. The dot in the center is known as the [[radix point]]. It separates the integer part on the left from the fraction part on the right. Furthermore, the value of number ''N'' in base ''r'' can be represented in '''polynomial form''' as

::<math>N_r = \sum^{n-1}_{i=-m} d_i r^i= (d_{n-2}r^{n-2} + d_{n-1}r^{n-1} + \cdots + d_1r^1 + d_0r^0 + d_{-1}r^{-1} + d_{-2}r^{-2} + d_{-m}r^{-m})_r</math>

Where '''d''' is the digit in the ith position.

=== notation examples (base 10, 2, and 16) ===
For example, consider the following number <math>49835.5825_{10}</math>. Note the ''10''. Subscripts are used to indicate a [[base]]; often, to avoid confusion, when presenting values in different basis. Following the polynomial equation stated above, we can express out number as:

::<math>
\begin{eqnarray*}
N_{10} &=& 49835.5825 \\
     &=& (d_4 d_3 d_2 d_1 d_0 \cdot d_{-1} d_{-2} d_{-3} d_{-4})_{10} \\
     &=& 4 \times 10^4 + 9 \times 10^3 + 8 \times 10^2 + 3 \times 10^1 + 5 \times 10^0 + 5 \times 10^{-1} + 8 \times 10^{-2} + 2 \times 10^{-3} + 5 \times 10^{-4} \\
     &=& 40000 + 9000 + 800 + 30 + 5 + 0.5 + 0.08 + 0.002 + 0.0005 \\
     &=& 49835.5825
\end{eqnarray*}
</math>


Now consider the following number <math>10101110.011_{2}</math>. Note that the subscript is ''2'' indicating the number is in [[base-2]]. We can express this binary number in polynomial form as well:

::<math>
\begin{eqnarray*}
N_{2} &=& 10101110.011 \\
     &=& (d_7 d_6 d_5 d_4 d_3 d_2 d_1 d_0 \cdot d_{-1} d_{-2} d_{-3})_{2} \\
     &=& 1 \times 2^7 + 0 \times 2^6 + 1 \times 2^5 + 0 \times 2^4 + 1 \times 2^3 + 1 \times 2^2 + 1 \times 2^1 + 0 \times 2^0 + 0 \times 2^{-1} + 1 \times 2^{-2} + 1 \times 2^{-3} \\
     &=& 128 + 32 + 8 + 4 + 2 + 0.25 + 0.125 \\
     &=& 174.375_{10} \\
\end{eqnarray*}
</math>

Note that as part of the process we've actually converted the number to decimal.
@@ Line 1: / Line 1: @@
-[[File:number systems.svg|right|300px]]
+'''Number systems''' are a mathematical notation for representing numbers of a given [[number set|set]]. They are the foundation for conveying, quantifying, and manipulating [[data]].
-A '''number system''' is a mathematical notation for representing numbers of a given [[number set|set]]. They are the foundation for conveying, quantifying, and manipulating [[data]].
-Number systems are mainly classified according to [[number notation|notations]] ([[positional notation]] vs [[sign-value notation]]) and their [[base]]. Today, we largely use the [[Arabic numerals]] which is a [[base-10]] positional notation numbering system. Machines on the other hand may use a different number system - such as the [[binary number system]].
+Number systems are mainly classified according to [[number notation|notations]] ([[positional notation]] vs [[sign-value notation]]) and their [[base]]. Today, we largely use the [[Arabic numerals]] which is a [[base-10]] positional notation numbering system. Machines on the other hand may use a different number system - such as the [[base-2]].
 == Notation ==
@@ Line 9: / Line 8: @@
 ::<math>N_r = (d_{n-2} d_{n-1} \cdots d_2 d_1 d_0 \cdot d_{-1} d_{-2} d_{-3} \cdots d_{-m})_r</math>
-Where '''r''' is the [[radix]] or base. The base represents the number of digits in the number system. '''d''' are the digits defined for that given radix. The dot in the center ('''⋅''') is known as the [[radix point]]. It separates the integer part on the left from the fractional portion on the right. Furthermore, the value of number ''N'' in base ''r'' can be represented in '''polynomial form''' as
+Where '''r''' is the [[radix]] or the number of digits in the number system and '''d''' are the digits defined for that given radix. The dot in the center is known as the [[radix point]]. It separates the integer part on the left from the fraction part on the right. Furthermore, the value of number ''N'' in base ''r'' can be represented in '''polynomial form''' as
 ::<math>N_r = \sum^{n-1}_{i=-m} d_i r^i= (d_{n-2}r^{n-2} + d_{n-1}r^{n-1} + \cdots + d_1r^1 + d_0r^0 + d_{-1}r^{-1} + d_{-2}r^{-2} + d_{-m}r^{-m})_r</math>
-Where '''d''' is the digit in the ith position. When a number has no fractional portion, the number can be more accurately called an [[integer]]. Conversely, if a number has no integer part, it is called a fractional number or simply a [[fraction]].
+Where '''d''' is the digit in the ith position.
-On various occasions, a number might be written in the form <math>N_r</math> where the subscript ''r'' is the [[radix]] of number ''N''. Subscripts are used to indicate a [[base]]; often, to avoid confusion, when presenting values in different basis.
+=== notation examples (base 10, 2, and 16) ===
+For example, consider the following number <math>49835.5825_{10}</math>. Note the ''10''. Subscripts are used to indicate a [[base]]; often, to avoid confusion, when presenting values in different basis. Following the polynomial equation stated above, we can express out number as:
-=== Decimal Number System ===
-{{main|decimal}}
-For the most part, humans use the decimal number system (base-10) for all day-to-day activities. It is the number system we learn and grow up with hence the most familiar to us. In a base-10 number system there are 10 distinct digits: <math>\{0,1,2,3,4,5,6,7,8,9\}</math>. Consider the following number <math>49835.5825_{10}</math>. Note the ''10''. We can express that number in polynomial form as
-::<math>
-\begin{align}
-N_{10} &= 49835.5825 \\
-     &= (d_4 d_3 d_2 d_1 d_0 \cdot d_{-1} d_{-2} d_{-3} d_{-4})_{10} \\
-     &= 4 \times 10^4 + 9 \times 10^3 + 8 \times 10^2 + 3 \times 10^1 + 5 \times 10^0 + 5 \times 10^{-1} + 8 \times 10^{-2} + 2 \times 10^{-3} + 5 \times 10^{-4} \\
-     &= 40000 + 9000 + 800 + 30 + 5 + 0.5 + 0.08 + 0.002 + 0.0005 \\
-     &= 49835.5825_{10}
-\end{align}
-</math>
-Now consider the fractional decimal number <math>0.938_{10}</math>. Since there is no integer part, our exponents start at 0 and decrease with each additional digit:
-::<math>
-\begin{align}
-N_{10} &= 0.938 \\
-     &= (d_{-1} d_{-2} d_{-3})_{10} \\
-     &= 9 \times 10^{-1} + 3 \times 10^{-2} + 8 \times 10^{-3} \\
-     &= 0.9 + 0.03 + 0.008 \\
-     &= 0.938_{10}
-\end{align}
-</math>
-=== Binary Number System ===
-{{main|binary}}
-In the binary number system, the [[radix]] is 2 - i.e. a number system capable of only representing two discrete values: <math>\{0,1\}</math>. Let's consider the following number <math>10101110.011_{2}</math>. Note that the subscript is ''2''. We can express this [[binary number]] in polynomial form as follows:
-::<math>
-\begin{align}
-N_{2} &= 10101110.011 \\
-     &= (d_7 d_6 d_5 d_4 d_3 d_2 d_1 d_0 \cdot d_{-1} d_{-2} d_{-3})_{2} \\
-     &= 1 \times 2^7 + 0 \times 2^6 + 1 \times 2^5 + 0 \times 2^4 + 1 \times 2^3 + 1 \times 2^2 + 1 \times 2^1 + 0 \times 2^0 + 0 \times 2^{-1} + 1 \times 2^{-2} + 1 \times 2^{-3} \\
-     &= 128 + 32 + 8 + 4 + 2 + 0.25 + 0.125 \\
-     &= 174.375_{10} \\
-\end{align}
-</math>
-Note that as part of the process we've actually converted the number to [[decimal]].
-=== Octal Number System ===
-{{main|octal}}
-The octal number system as the name implies uses [[radix]] of 8; i.e. the number system is represented via 8 discrete values: <math>\{0,1,2,3,4,5,6,7\}</math>. Let's take the number <math>703.104_8</math>,
 ::<math>
-\begin{align}
+\begin{eqnarray*}
-N_{8} &= 703.104 \\
+N_{10} &=& 49835.5825 \\
-      &= (d_2 d_1 d_0 \cdot d_{-1} d_{-2} d_{-3})_{16} \\
+      &=& (d_4 d_3 d_2 d_1 d_0 \cdot d_{-1} d_{-2} d_{-3} d_{-4})_{10} \\
-      &= 7 \times 8^2 + 0 \times 8^1 + 3 \times 8^0 + 1 \times 8^{-1} + 0 \times 8^{-2} + 4 \times 8^{-3} \\
+      &=& 4 \times 10^4 + 9 \times 10^3 + 8 \times 10^2 + 3 \times 10^1 + 5 \times 10^0 + 5 \times 10^{-1} + 8 \times 10^{-2} + 2 \times 10^{-3} + 5 \times 10^{-4} \\
-      &= 448 + 3 + 0.125 + 0.0078125 \\
+      &=& 40000 + 9000 + 800 + 30 + 5 + 0.5 + 0.08 + 0.002 + 0.0005 \\
-      &= 451.1328125_{10}
+      &=& 49835.5825
-\end{align}
+\end{eqnarray*}
 </math>
-An interesting property of a base-8 system being <math>2^3</math> is that converting a number from [[binary]] to [[octal]] can easily done by breaking the number number into groups of 3 [[bit]]s and converting each group individually into octal. Octal being 8 values means each group of 3 binary bits equates to a single octal digit. For example consider the following number <math>1010011101_2</math>. We can break the number into groups of 3 bits: <math>[001]_2 [010]_2 [011]_2 [101]_2</math>. Each of those groups can now be converted to octal independently: <math>[1]_8 [2]_8 [3]_8 [5]_8 = 1235_8</math>. Note that the conversion from octal back to binary can just as easily be done by simple converting each individual octal digit back into a group of 3 binary digits.
-=== Hexadecimal Number System ===
+Now consider the following number <math>10101110.011_{2}</math>. Note that the subscript is ''2'' indicating the number is in [[base-2]]. We can express this binary number in polynomial form as well:
-{{main|Hexadecimal}}
-The Hexadecimal number system or base-16 has 16 discrete digits. Those digits have traditionally been <math>\{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F\}</math>. Note that A through F are decimal 10 through 15, respectively. In this example we'll use the [[hexadecimal|hex]] number <math>FDAE.F5F_{16}</math>.
 ::<math>
-\begin{align}
+\begin{eqnarray*}
-N_{16} &= FDAE.F5F \\
+N_{2} &=& 10101110.011 \\
-      &= (d_3 d_2 d_1 d_0 \cdot d_{-1} d_{-2})_{16} \\
+      &=& (d_7 d_6 d_5 d_4 d_3 d_2 d_1 d_0 \cdot d_{-1} d_{-2} d_{-3})_{2} \\
-      &= F \times 16^3 + D \times 16^2 + A \times 16^1 + E \times 16^0 + F \times 16^{-1} + 5 \times 16^{-2} + F \times 16^{-3} \\
+      &=& 1 \times 2^7 + 0 \times 2^6 + 1 \times 2^5 + 0 \times 2^4 + 1 \times 2^3 + 1 \times 2^2 + 1 \times 2^1 + 0 \times 2^0 + 0 \times 2^{-1} + 1 \times 2^{-2} + 1 \times 2^{-3} \\
-     &= 15 \times 16^3 + 13 \times 16^2 + 10 \times 16^1 + 14 \times 16^0 + 15 \times 16^{-1} + 5 \times 16^{-2} + 15 \times 16^{-3} \\
+      &=& 128 + 32 + 8 + 4 + 2 + 0.25 + 0.125 \\
-      &= 61440  + 3328 + 160 + 15 + 0.9375 + 0.01953125 + 0.003662109375 \\
+      &=& 174.375_{10} \\
-      &\cong 64943.9606934_{10}
+\end{eqnarray*}
-\end{align}
 </math>
-Note that the final value is rounded as a result of fraction estimation. Note that just like [[octal]] is also a power of 2 (<math>2^4</math>), meaning conversion from binary to hex can be done by simply breaking down a [[binary number]] into groups of 4 bits and converting each group individually. For example, consider the number <math>101101011110001_2</math> which can be broken down into <math>[0101]_2[1010]_2[1111]_2[0001]_2 = [5]_{16}[A]_{16}[F]_{16}[1]_{16} = 5AF1_{16}</math>. Converting a number back from hex to binary is done by simply converting each individual hex digit back into a group of 4 bits.
+Note that as part of the process we've actually converted the number to decimal.